Mathematics COMPLEX NUMBERS- Argand Plane and Polar Representation
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Topics Covered

`star` Argand Plane
`star` Modulus of the complex number in the Argand plane
`star` Representation of a complex number and its conjugate
`star` Polar representation of a complex number

Argand Plane

`\color{green} ✍️ ` The plane having a complex number assigned to each of its point is called the `color(blue)"complex plane or the Argand plane."`

`\color{green} ✍️ ` We already know that corresponding to each ordered pair of real numbers `(x, y),` we get a unique point in the `XY` plane and vice-versa with reference to a set of mutually perpendicular lines known as the x-axis and the y-axis.

`\color{green} ✍️ ` The complex number `x + iy` which corresponds to the ordered pair `(x, y)` can be represented geometrically as the unique point `P(x, y)` in the `XY`-plane and vice-versa.

`\color{green} ✍️ ` Some complex numbers such as `2 + 4i, – 2 + 3i, 0 + 1i, 2 + 0i, – 5 –2i` and `1 – 2i` which correspond to the ordered pairs `(2, 4), ( – 2, 3), (0, 1), (2, 0), ( –5, –2),` and `(1, – 2),` respectively, have been represented geometrically by the points `A, B, C, D, E,` and `F,` respectively in the Fig 5.1.

`\color{green} ✍️ ` The points on the `x`-axis corresponds to the complex numbers of the form `a + i 0`
and the points on the `y`-axis corresponds to the complex numbers of the form `0 + i b.`

`\color{green} ✍️ ` The `x`-axis and `y`-axis in the Argand plane are called, respectively, the `color(blue)"real axis"` and the `color(blue)"imaginary axis."`

modulus of the complex number in the Argand plane

`\color{green} ✍️ ` `color(blue)(|x + iy| = sqrt(x^2 + y^2))` is the distance between the point `P(x, y)` to the origin `O (0, 0)` (Fig 5.2).

representation of a complex number and its conjugate

`\color{green} ✍️ ` The representation of a complex number `color(blue)(z = x + iy)` and

its conjugate `color(blue)(z = x – iy)` in the Argand plane are, respectively, the points `color(blue)(P (x, y))` and `color(blue)(Q (x, – y)).`

`\color{green} ✍️` Geometrically,
`color(blue)("the point (x, – y) is the mirror image of the point (x, y) on the real axis")` (Fig 5.3).

Polar representation of a complex number

`\color{green} ✍️` Let the point `P` represent the nonzero complex number `color(blue)(z = x + iy.)`

`\color{green} ✍️` Let the directed line segment `OP` be of length `r` and `θ` be the angle which `OP` makes with the positive direction of `x`-axis (Fig 5.4).

`\color{green} ✍️` We may note that the point `P` is uniquely determined by the ordered pair of real numbers `color(blue)((r, θ)),` `color(red)("called the polar coordinates of the point P.")` We consider the origin as the pole and the positive direction of the `x` axis as the initial line.

`\color{green} ✍️` We have, `color(blue)(x = r cos θ, y = r sin θ)` and therefore, `color(blue)(z = r (cos θ + i sin θ).)` The latter is `color(red)("said to be the polar form of the complex number. ")`

`\color{green} ✍️` Here `color(blue)(r = sqrt(x^2 + y^2) = |z|)` is the modulus of `z` and `θ` is called the argument (or amplitude) of `z` which is denoted by `arg z.`

`\color{green} ✍️` For any complex number `z ≠ 0,` there corresponds only one value of `θ` in `0 ≤ θ < 2π.` However, any other interval of length `2π,` for example `– π < θ ≤ π,` can be such an interval.

`\color{green} ✍️` We shall take the value of `θ` such that `color(red)(– π < θ ≤ π),` called `color(red)("principal argument of z")` and is denoted by `arg z .` (Figs. 5.5 and 5.6)
Q 3018712609

Represent the complex number `z = 1+i sqrt3` in the polar form.

Solution:

Let `1 = r cos θ, sqrt3 = r sintheta`

By squaring and adding, we get

`r^2 (cos^2 theta+sin^2 theta) = 4`

i.e. `r = sqrt3 =` (conventionally, r > 0)

Therefore `cos theta = 1/2 , sintheta = sqrt3/2` which gives `theta = pi/3`

Therefore, required polar form is `z = 2 ( cos \ \ pi/3 + i sin \ \ pi/3)`

The complex number `z = 1+i sqrt3` is represented as shown in Fig
Q 3088012807

Convert the complex number `(-16)/(1+i sqrt3)` into polar form.

Solution:

The given complex number `(-16)/(1+i sqrt3) = (-16)/(1+i sqrt3) xx (1- i sqrt3)/(1-i sqrt3)`

` = (-16 (1-i sqrt3))/{1- (i sqrt3)^2} = { -16 (1-i sqrt3)}/(1+3) = -4(-i sqrt3) = -4+i sqrt3`

Let `-4 = rcostheta , sqrt3 = rsintheta`

By squaring and adding, we get

`16+48 = r^2 ( cos^2 theta +sin^2 theta)`

where gives `r^2 = 64 , i. e , r = 8`

Hence `costheta = -1/2 , sintheta = sqrt3/8`

`theta = pi- pi/3 = (2pi)/3`

Thus, the required polar form is `8 ( cos \ \ (2pi)/3 + i sin \ \ (2pi)/3)`

 
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